Verbolten (Project Announcement Fall 2011 Through Opening Discussion August 2012)
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RE: Verbolten
I think he was talking about the horizontal acceleration force, not the traditional vertical g force (which of course is 1G). I looked up Kingda Ka and kept finding 1.67G listed for the force of its launch (mostly horizontal). So it seems reasonable that Verbolten could have a 1G launch.
Or I could could be wrong. After all, I have Dynamics and Physics next semester...
I think he was talking about the horizontal acceleration force, not the traditional vertical g force (which of course is 1G). I looked up Kingda Ka and kept finding 1.67G listed for the force of its launch (mostly horizontal). So it seems reasonable that Verbolten could have a 1G launch.
Or I could could be wrong. After all, I have Dynamics and Physics next semester...
RE: Verbolten
Darn Physics, it is so confusing, well the launches do seem to be horizontal and not vertical, and the track from the looks of it doesn't have any major drop other than the river and the free fall drops. So I think it is safe to say, he was most likely talking about horizontal g-force.
Darn Physics, it is so confusing, well the launches do seem to be horizontal and not vertical, and the track from the looks of it doesn't have any major drop other than the river and the free fall drops. So I think it is safe to say, he was most likely talking about horizontal g-force.
RE: Verbolten
Haha, if you want someone good with physics block me out. I fail like every test. The funny part is, I swear I started to understand some of it and then bam, it changed on me.
Haha, if you want someone good with physics block me out. I fail like every test. The funny part is, I swear I started to understand some of it and then bam, it changed on me.
RE: Verbolten
Larry said specifically and I quote, "we have a 1g launch". This will launch the train to 55-60mph quickly, and pull
the same linear Gs as a sports car accelerating would (which the train is emulating). He didn't misspeak.
It's all good. If anyone has ridden Hulk at IOA, the launch will feel similar to that. Probably a little smoother with the LIMs and all. It'll be fun.
Larry said specifically and I quote, "we have a 1g launch". This will launch the train to 55-60mph quickly, and pull
the same linear Gs as a sports car accelerating would (which the train is emulating). He didn't misspeak.
It's all good. If anyone has ridden Hulk at IOA, the launch will feel similar to that. Probably a little smoother with the LIMs and all. It'll be fun.
RE: Verbolten
hey,
I think that guy used to work for six flags!...who knew? lol
hey,
I think that guy used to work for six flags!...who knew? lol
RE: Verbolten
Think Griffon before the water splash...
Anyways, I am glad that the park is finally giving out some updates, the GP are starting to gain interest in the ride.
redsoxfan787 said:
Think Griffon before the water splash...
Anyways, I am glad that the park is finally giving out some updates, the GP are starting to gain interest in the ride.
RE: Verbolten
Sounds like someone has been reading my posts elsewhere. Why did you call me out? That is the only reason I am weighing in, I wanted to watch the banter of random guesses for a bit but whatever.
Flat acceleration typically is not attribute to anything of "1G launch." For example. RnR at Hollywood studios has 5G's in the transition from the launch strait to the where the first loop begin to turn upward. The launch in this case the upward angle is a straight plane; because of that there are no vertical forces in action. We are solely dealing with horizontal forces.
a=dv/rt=d^2/dt^2
In this case dV=v1-v0. v1 represent final speed subtrated by starting speed.
In layman's terms, you would have to go from ~5mph to ~55mph in just under 2.5 seconds to acheive 1G. The slight inclination can make v1 slightly lower since it is heading upward. The upward angle requres more force for the vehicle to reach v1 within the designated time. Final word. Expect it to be no faster than 55mph AT most but leaning more toward 45/50mph due to the angle of ascent.
We can say that 5mph-55mph on a level plane is ~.91G. Factor in angles and the rearward gravitational pull then it would factor to just over 1G. I highly doubt you will hit the segment at 5mph, however, but closer to 10mph. 10mph-55mph on a level plane is ~.82G. If I cared enough I could take the angle, distance, and estimated v0 and calculate fairly confident to within a thousandth of the of Gs that a rider will incur. I, however, could not careless what it is to do that much work.
The link posted previously does not allow the factoring of the angular accleration or vector. It does contain the same basic formula that I posted, though. It seems to be more focused to force acceleration across various vectors and leaves out a bit of what we are focusing on with this subject.
To the note of "faster than any sports car." Any sports car with a 0-60 of 2.7 or under pulls at least 1G.
1.09G
Bugatti Veyron 2005: 2.5s
Caparo T1 2007: 2.5s
1.05G
Orca SC7 2005: 2.6s
Ultima GTR 2006: 2.6s
1.01G
Porsche 911 Turbo S: 2.7s
Nissan GTR: 2.7s
AoenOne said:
Sounds like someone has been reading my posts elsewhere. Why did you call me out? That is the only reason I am weighing in, I wanted to watch the banter of random guesses for a bit but whatever.
Flat acceleration typically is not attribute to anything of "1G launch." For example. RnR at Hollywood studios has 5G's in the transition from the launch strait to the where the first loop begin to turn upward. The launch in this case the upward angle is a straight plane; because of that there are no vertical forces in action. We are solely dealing with horizontal forces.
a=dv/rt=d^2/dt^2
In this case dV=v1-v0. v1 represent final speed subtrated by starting speed.
In layman's terms, you would have to go from ~5mph to ~55mph in just under 2.5 seconds to acheive 1G. The slight inclination can make v1 slightly lower since it is heading upward. The upward angle requres more force for the vehicle to reach v1 within the designated time. Final word. Expect it to be no faster than 55mph AT most but leaning more toward 45/50mph due to the angle of ascent.
We can say that 5mph-55mph on a level plane is ~.91G. Factor in angles and the rearward gravitational pull then it would factor to just over 1G. I highly doubt you will hit the segment at 5mph, however, but closer to 10mph. 10mph-55mph on a level plane is ~.82G. If I cared enough I could take the angle, distance, and estimated v0 and calculate fairly confident to within a thousandth of the of Gs that a rider will incur. I, however, could not careless what it is to do that much work.
The link posted previously does not allow the factoring of the angular accleration or vector. It does contain the same basic formula that I posted, though. It seems to be more focused to force acceleration across various vectors and leaves out a bit of what we are focusing on with this subject.
To the note of "faster than any sports car." Any sports car with a 0-60 of 2.7 or under pulls at least 1G.
1.09G
Bugatti Veyron 2005: 2.5s
Caparo T1 2007: 2.5s
1.05G
Orca SC7 2005: 2.6s
Ultima GTR 2006: 2.6s
1.01G
Porsche 911 Turbo S: 2.7s
Nissan GTR: 2.7s
RE: Verbolten
Because of the answer I knew you would give... I like to watch you crap on everyones logic.
Atlantis said:
Because of the answer I knew you would give... I like to watch you crap on everyones logic.
RE: Verbolten
I take it you have been through the "Strange Sounds Popping Up" thread elsewhere.
This. The transition to the upward angle post-launch creates 4Gs. RnR pulls around 4.6 heading to the first loop. 0-220mph in 2.5 seconds would create 4.0Gs on a level plane. I had to lol at assuming a launch would produce that.
AoenOne said:
I take it you have been through the "Strange Sounds Popping Up" thread elsewhere.
waross said:
This. The transition to the upward angle post-launch creates 4Gs. RnR pulls around 4.6 heading to the first loop. 0-220mph in 2.5 seconds would create 4.0Gs on a level plane. I had to lol at assuming a launch would produce that.
RE: Verbolten
.
Larry didn't misspeak. He was just commenting on how smooth a LSM launch is and here is the reason why they are using LSM's over LIM's.
Since Atlantis did the "1g" post, it's time for me to do the LSM postwaross said:
. Larry didn't misspeak. He was just commenting on how smooth a LSM launch is and here is the reason why they are using LSM's over LIM's.
For those wondering how they are going to stop the trains, it will be the alternate-pole permanent magnets on the other side, (which is mounted on the trains) so when the train reach the the metal break fins it causes the train to slow to a stop. These same magnets (used for stopping) run trough active winding when the train reaches the launch section of track and it causes the train to move or be launched.
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