Have a question? Post it here! Have an answer to a question that alot of people ask? Post that here as well! This thread is for any questions, and answers, that you may about Busch Gardens Williamsburg.
Alpenghöst said:If I were to drop a rock which weighed 1.86 lbs off the top of Griffon, how long would it take to knock out a small child who disobeyed the safety warnings and was messing about in the flower bed below the drop?
Alpenghöst said:If I were to drop a rock which weighed 1.86 lbs off the top of Griffon, how long would it take to knock out a small child who disobeyed the safety warnings and was messing about in the flower bed below the drop?
Party Rocker said:I learned something like this in January!
I learned to place the situation on a graph, with an X-axis and a Y-axis. Which means the rock wouldn't go straight down, but veer off some. With all the information from the problem and that I put into the equations I used, this is what I did.
I first searched for the time to find an accurate velocity. To do this I used this equation (Final Distance = Initial Distance + Initial Velocity * Time + .5 * Acceleration * Time squared) with my Y-axis. I took out the Initial Distance since that was 0 and I took out the Initial Velocity * Time since the Initial Velocity is 0 and anything times 0 is 0. This leaves me with Final Distance = .5 * Acceleration * Time squared. I rearranged the problem to equal my Time and got Time = the square root of 2 * Final Distance divided by the Acceleration. Inserting numbers I get Time = 2 * 2m divided by a positive 9.8 m/s squared. I used 2m to suggest the rock may have landed 2m away from its original spot instead of right under where it was dropped. I ended up with a time of .64 seconds. In other words, it took .64 seconds for the rock to fall.
Now I used my new found time to get me my velocity. I used the equation the Velocity = Distance divided by Time. I used this equation on my X-axis portion of the problem. Time is the same for the Y and X axis's. So With that said, I got 62m divided by .64 seconds and got a Velocity of 96.88 m/s.
Of course this is how I have been taught in a public school setting and I had to change some numbers and add some numbers. I will ask my Physics teacher if I did the math right when I see him.
Swiftman said:Not even 24 hours after this thread opened and it has already gone up in flames. You know, I almost find this impressive.
Anyway, can we try to keep the questions serious?
redsoxfan787 said:Well, it's going to be an extra weekend longer
Haberdasher1973 said:According to the Fun Tracker, it begins September 14th and runs through October 28th.
Swiftman said:2010's ran from the 24th of September to the 31st of October (6 weeks)
2011's started on the 23rd of September and ended on the 30th of October (6 weeks)
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